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0.5x^2+5x-15=0
a = 0.5; b = 5; c = -15;
Δ = b2-4ac
Δ = 52-4·0.5·(-15)
Δ = 55
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{55}}{2*0.5}=\frac{-5-\sqrt{55}}{1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{55}}{2*0.5}=\frac{-5+\sqrt{55}}{1} $
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